Question

ASAP PLEASE please please

Answer 1

`{ \qquad\qquad\huge\underline{{\sf Answer}}}`

Let's solve ~

`\qquad \sf  \dashrightarrow \: \cfrac{1}{b} + 10 = \cfrac{9}{b} + 7`

`\qquad \sf  \dashrightarrow \: \cfrac{9}{b} - \cfrac{1}{b} = 10 - 7`

`\qquad \sf  \dashrightarrow \: \cfrac{8}{b} = 3`

`\qquad \sf  \dashrightarrow \: b = \cfrac{8}{3}`

Answer 2

`b=(8)/(3)`

Explanation:

Given equation:

`(1)/(b)+10=(9)/(b)+7`

Subtract 10 from both sides:

`\implies (1)/(b)+10-10=(9)/(b)+7-10`

`\implies (1)/(b)=(9)/(b)-3`

Multiply both sides by b:

`\implies (1 \cdot b)/(b)=(9 \cdot b)/(b)-3b`

`\implies 1=9-3b`

Add 3b to both sides:

`\implies 1+3b=9-3b+3b`

`\implies 3b+1=9`

Subtract 1 from both sides:

`\implies 3b+1-1=9-1`

`\implies 3b=8`

Divide both sides by 3:

`\implies (3b)/(3)=(8)/(3)`

`\implies b=(8)/(3)`