Question

3. Find the coordinates of the midpoint of Asif A(-4, 7) and S(5,3). number 9 please

Answer 1

(
`(1)/(2)`, 5 )

Explanation:

Given endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is

(
`(x_(1)+x_(2) )/(2)` ,
`(y_(1)+y_(2) )/(2)` )

Here (x₁, y₁ ) = A (- 4, 7) and (x₂, y₂ ) = B (5, 3 ) , then

midpoint = (
`(-4+5)/(2)` ,
`(7+3)/(2)` ) = (
`(1)/(2)` ,
`(10)/(2)` ) = (
`(1)/(2)` , 5 )

Answer 2

Explanation:

slope = (x1 + x2/2 , y1 + y2/2)

x1 = -4

x2 = 5

y1 = 7

y2 = 3

after inserting the values we got,

→ ( -4 + 5/2 , 7+3/2 )

→ ( 1/2 , 10/2 )

→ ( 0.5 , 5 )

hope this answer helps you dear...take care mau u have a great day ahead!...