Question

Neeed help please pleasee

Answer 1

Y = 2+- square root of 6

Explanation:

Answer 2

`{ \qquad\qquad\huge\underline{{\sf Answer}}}`

Lets solve ~

Let's calculate its discriminant ~

`\qquad \sf  \dashrightarrow \: {y}^(2) -4y - 2=0`

• a = 1

• b = -4

• c = -2

`\qquad \sf  \dashrightarrow \: discriminant = {b}^(2) - 4ac`

`\qquad \sf  \dashrightarrow \: d = (-4) {}^(2) - (4 * 1* - 2)`

`\qquad \sf  \dashrightarrow \: d = 16 - ( - 8)`

`\qquad \sf  \dashrightarrow \: d = 24`

`\qquad \sf  \dashrightarrow \: \sqrt {d }= 2 √(6)`

So, by quadratic formula :

`\qquad \sf  \dashrightarrow \: y= \frac{ - {b}^{} \pm √(d) }{2a}`

`\qquad \sf  \dashrightarrow \: y = \frac{ - {(-4)}^{} \pm 2√(6) }{2 ×1}`

`\qquad \sf  \dashrightarrow \: \:y=\pm \cfrac{2(2\pm√(6) }{2}`

`\qquad \sf  \dashrightarrow \: \:y= { 2+√(6)}{} \: \: and \: \: t = {2-√(6)}{}`