
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
Do you remember that we need to get x by itself to find its value?
We should do this:
⇨ Add 6 to both sides

On the left hand side (lhs), the 6s add up to zero; on the right hand side (rhs), the -2 and 6 result in 4. Hence

Now divide both sides by 4

Simplifying fractions gives us

* what this means is: numbers less than 1 will make the statement true
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Substitute 1 into the original inequality



Do the arithmetic

Hope that helped