Question

Complete the equation of the line through
(-10, 3) and (-8, -8).

Answer 1

The answer is y = -5.5x - 52.

First, let's find the slope of the line.

m = Δy/Δx

• m = -8 - 3 / -8 - (-10)
• m = -11 / -8 + 10
• m = -11/2
• m = -5.5

Now, substitute the slope and one of the given points in the point slope equation.

y - y₁ = m (x - x₁)

• y - 3 = -5.5 (x - (-10))
• y - 3 = -5.5 (x + 10)
• y - 3 = -5.5x - 55
• y = -5.5x - 52

Answer 2

Answer: y=-5,5x-52.

Explanation:

Equation of a straight line

`\displaystyle\\\boxed {(x-x_1)/(x_2-x_1)=(y-y_1)/(y_2-y_1) }`

`(-10;3)\ \ \ \ \ (-8;-8).\\\displaystyle(x-(-10))/(-8-(-10)) =(y-3)/(-8-3)\\ (x+10)/(-8+10)=(y-3)/(-11) \\ (x+10)/(2)=(y-3)/(-11) \\-11*(x+10)=2*(y-3)\\-11x-110=2y-6\\2y=-11x-104\ |:2\\y=-5,5x-52.`