Question

1a, b/46 = 50/23 1b. 34/d = 68/44​

Answer 1

•
`b = \bf 100`

•
`d = \bf 22`

Explanation:

To solve these questions, we need to rearrange the equations to make the unknown variables the subject of the equations.

1a.

`(b)/(46) = (50)/(23)`

⇒
`b = (50 * 46)/(23)` [multiplying both sides by 46]

⇒
`b = \bf 100`

1b.

`(34)/(d) = (68)/(44)`

⇒
`34 = (68 * d)/(44)` [multiplying both sides by d]

⇒
`34 * 44 = 68 * d` [multiplying both sides by 44]

⇒
`\frac {34 * 44}{68} = d` [dividing both sides by 68]

⇒
`d = \bf 22`

Answer 2

1a. 100, 1b. 22

Explanation:

1a. Given information from the question:

`(b)/(46) = (50)/(23) \\ 23b = (50)(46) \: (cross \: multiply) \\ b = (50 * 46)/(23) \\ = 50 * 2 \\ = 100`

1b. Given information from the question:

`(34)/(d) = (68)/(44) \\ 68d = (34)(44) \: (cross \: multiply)\\ \\ d = (34 * 44)/(68) \\ d = (44)/(2) \\ = 22`