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A 7.74 L balloon is filled with water at 3.88 atm. If the balloon is squeezed into a 0.23 L beaker and does NOT burst, what is the pressure of water in the balloon?

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Answer:

131 atm

Step-by-step explanation:

To find the new pressure, you need to use Boyle's Law:

P₁V₁ = P₂V₂

In this equation, "P₁" and "V₁" represent the initial pressure and volume. "P₂" and "V₂" represent the final pressure and volume. You can find the new pressure (P₂) by plugging the given values into equation and simplifying.

P₁ = 3.88 atm P₂ = ? atm

V₁ = 7.74 L V₂ = 0.23 L

P₁V₁ = P₂V₂ <----- Boyle's Law

(3.88 atm)(7.74 L) = P₂(0.23 L) <----- Insert values

30.0312 = P₂(0.23 L) <----- Simplify left side

131 = P₂ <----- Divide both sides by 0.23

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