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Factor completely 4x^2 − 32

1 Answer

4 votes

Answer:
4(x+2√(2))(x-2√(2))

Explanation:

We can first take out the common factor of 4, as both 4x² and -32 are divisible by 4.


4(x^2-8)

From here, we can assume that x²-8 is a difference of two squares even though 8 is not a perfect square.

For review, a difference of two squares
a^2-b^2 can be factored into
(a+b)(a-b).


4(x^2-8)\\4(x+√(8))(x-√(8))\\4(x+2√(2))(x-2√(2))

User Ian Carter
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