Question

A bag contains 2 red marbles, 6 blue marbles and 7 green marbles. If two marbles are drawn out of the bag, what is the probability, to the nearest 1000th, that both marbles drawn will be red?

Answer 1

0.01

Explanation:

1) the rule is: {required probability}={probability of 2 red marbles} / {all possible combinations 2 of 15};

2) according to the rule above the required probability is:

`(C^2_2*C_(13)^0)/(C^2_(15))=(2!*13!)/(15!)=(2)/(14*15)=(1)/(105)=0.0095238=0.01.`