Question

Solve question in image (yr 8 math, 40 pt)

Answer 1

Answer: y = 3

Explanation:

Given equation

`(5y~-~3)/(4) ~+~6~=~3y`

Multiply 4 on both sides (to eliminate fraction)

`(5y~-~3)/(4) *4~+~6*4~=~3y*4`

`(5y~-~3)~+~24~=~12y`

Expand parenthesis and combine like terms

`5y~-~3~+~24~=~12y`

`5y~+~21~=~12y`

Subtract 5y on both sides

`5y~+~21~-~5y~=~12y~-~5y`

`21~=~7y`

Divide 7 on both sides

`21~/~7~=~7y~/~7`

`\Large\boxed{y=3}`

Hope this helps!! :)

Please let me know if you have any questions

Answer 2

y = 3

Explanation:

(5y - 3)/4 + 6 = 3y

5y - 3 + 24 = 12y

7y = 21

y = 3

Check.

(5*3 - 3)/4 + 6 = 3*3

(15 - 3)/4 + 6 = 9

12/4 + 6 = 9

3 + 6 = 9

9 = 9