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Use special right triangles to find the value of the variables no decimal answers

Use special right triangles to find the value of the variables no decimal answers-example-1
User Raam
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2 Answers

4 votes

Answer:

Below in bold.

Explanation:

The first triangle is a 30-60-90 triangle,

so the sides are in the ratio 2 : 1 : √3, where 2 is the hypotenuse, the 1 is adjacent to 60 degree angle and the √3 is opposite the 60 degree angle.

So x = 1/2 * 32 = 16

and y = 16√3 or 27.71 to nearest hundredth.

The second one is the same special triangle, so

√3/2 = 12/b

b = 24/√3

= 8√3 or 13.86 to nearest hundredth.

a = 1/2 b = 4√3 or 6.93 to nearest hundredth.

User Sumesh TG
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4.1k points
1 vote

Explanation:

This is trigonometry. Focusing on Y initially, we can see that Y is the opposite, and 32 is the hypotenuse. Therefore, we must use sin:


\sin(60) = (y)/(32)


y = \sin(60) * 32


y \approx28

Next X. We can see that X is the adjacent, and 32 is the hypotenuse, so we must use cos:


\cos(60) = (x)/(32)


x = \cos(60) * 32


x = 16

Now let's look at A. We can see that a is the adjacent, and 12 is the opposite, so we must use tan:


\tan(60) = (12)/(a)


a = (12)/( \tan(60) )


a \approx7

Now, B. We can see that B is the hypotenuse, and 12 is the opposite, so we must use sin:


\sin(60) = (12)/(b)


b = (12)/( \sin(60) )


b \approx14

User Mathias Verhoeven
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4.1k points