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How many joules are given off when 120 grams of water are cooled from 0C to -25C?

User Mark Sowul
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1 Answer

3 votes

Answer:

46 359 J

Step-by-step explanation:

You need heat of fusion of water: 334 J/g

and specific heat of ice : 2.093 j/g-C

120 * 334 = 40 080 J to make ice

+ 120 * 2.093 * 25 = 6279 J to chill the ice to -25 C

Total = = 46359 J

User Kristian Haga
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5.0k points