Question

Find three consecutive integers such that the sum of twice the smallest and 3 times the largest is 126

Answer 1

Explanation:

let the numbers be x,x+1,x+2 (x<x+1<x+2)

2x+3(x+2)=126

2x+3x+6=126

5x=126-6

5x=120

x=120/5=24

numbers are 24,24+1,24+2

or 24,25,26