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Find the surface area of the composite figure.

5 cm
6 cm
20 cm
4 cm
5 cm 4 cm
SA =
12 cm
-6 cm
[?] cm²

Find the surface area of the composite figure. 5 cm 6 cm 20 cm 4 cm 5 cm 4 cm SA = 12 cm-example-1
User Pkit
by
5.1k points

1 Answer

3 votes

Explanation:

we have 2 blocks, as the graphic shows.

the surface areas of both blocks are the sum of their 6 sides each.

the special thing about seeing them as "composite figure" is that 2 sides (one for each block) are partly or even completely blocking each other off from being seen, so these parts and whole side are not part of the combined surface area.

let's start with the large block :

it is 5cm × 6cm × 20cm.

its surface area is the sum of

top and bottom 5×6

front and back 20×5

left 20×6

visible right (20 - 12)×6 = 8×6

it is (20-12)cm long, because the short block

is 12cm high.

so, we have

2 times 5×6 =2×30 = 60 cm²

2 times 20×5 = 2×100 = 200 cm²

20×6 = 120 cm²

8×6 = 48 cm²

in total : 428 cm²

now the small block :

it is 4cm × 6cm × 12cm.

its surface area is the sum of

top and bottom 4×6

front and back 4×12

no left (completely covered by the large block)

right 6×12

so, we have

2 times 4×6 = 2×24 = 48 cm²

2 times 4×12 = 2×48 = 96 cm²

6×12 = 72 cm²

in total : 216 cm²

the complete surface area of the composite figure is

428 + 216 = 644 cm²

User Kkemple
by
5.2k points