Question

Please help with this i genuinely have no clue how to figure it out

Answer 1

`\huge\mathbb{ \underline{SOLUTION :}}`

Given:

`\longrightarrow\bold{f(x) = 4x^3 + 7x2 −x + c}`

`\longrightarrow\sf{578= 32+28 −2+ c}`

`\longrightarrow\sf{578 =58+ c}`

`\longrightarrow\sf{c = 578-58}`

`\huge \mathbb{ \underline{ANSWER:}}`

`\longrightarrow\sf{c= 520}`

Answer 2

Answer: c = 520

Explanation:

f(2) = 578 means that when x = 2, the value is equal to 578. We will plug these knowns in and then solve for c.

Given:

f(x) = 4x³ + 7x² - x + c

Substitute:

578 = 4(2)³ + 7(2)² - (2) + c

Distribute:

578 = 4 * 2³ + 7 * 2² - 2 + c

Raise to the power of 3 and 2:

578 = 4 * 8 + 7 * 4 - 2 + c

Multiply:

578 = 32 + 28 - 2 + c

Add:

578 = 60 - 2 + c

Subtract:

578 = 58 + c

Subtract 58 from both sides:

520 = c

Reflexive property:

c = 520