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Please help me solve this, random answers will be removed

Please help me solve this, random answers will be removed-example-1
User DJo
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1 Answer

2 votes

Answer:

m∠B ≈ 70.8°

Explanation:

The Law of Cosines relates three sides of a triangle and the angle opposite one of them.

Setup

The law of cosines tells you ...

b² = a² +c² -2ac·cos(B)

Solving for angle B, we get ...

B = arccos((a² +c² -b²)/(2ac))

where 'a' and 'c' are the sides adjacent to the angle of interest. We want angle B, so we can fill this formula as follows:

B = arccos((13² +11² -14²)/(2·13·11))

Solution

B = arccos(94/286)

B ≈ 70.812°

__

Additional comment

Another angle can be found using the Law of Sines.

A = arcsin(sin(70.812°)×13/14) ≈ 61.281°

Then angle C is ...

C = 180° -70.812° -61.281° = 47.907°

Please help me solve this, random answers will be removed-example-1
User AbreQueVoy
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