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Please help me solve this, random answers will be removed.

Please help me solve this, random answers will be removed.-example-1
User Hugeen
by
8.5k points

2 Answers

6 votes

Answer:

See below

Step-by-step explanation:

Here is one way .... I showed you how to use Law of cosines in another Q

use this to find CB

CB^2 = 13^2 + 21^2 - 2(13)(21) cos 91 <==== solve for CB

THEN use law of SINES to find angle B

sin B / 21 = sin 91 / CB (CB you found using law of cosines above)

User Kidd Tang
by
8.6k points
2 votes

Answer:

m∠B = 57.5°

Step-by-step explanation:

Use cosine rule:

a² = b² + c² - 2bc cos(A)

inserting values

a² = 21² + 13² - 2(21)(13) cos(91)

a² = 619.529

a = √619.529

a = CB = 24.89 km

Then use sine rule:

sin(A)/a = sin(B)/b

sin(91)/24.89 = sin(B)/21

sin(B) = 21sin(91)/24.89

sin(B) = 0.843583...

B = sin⁻¹(0.843583) = 57.52° ≈ 57.5°

User BlueBear
by
7.9k points

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