Question 1

PLS HELP ASAP! Ty

Let g(x)= 2x^2+3x-9 and h(x)=x^2+2x-6
Find (h-g)(2.1)

Question 2

${\qquad\qquad\huge\underline{{\sf Answer}}}$

Let's solve ~

$\qquad \sf  \dashrightarrow \: (h - g)(x)$

$\qquad \sf  \dashrightarrow \: h(x) - g(x)$

$\qquad \sf  \dashrightarrow \: {x}^(2) + 2x - 6 - (2 {x}^(2) + 3x - 9)$

$\qquad \sf  \dashrightarrow \: {x}^(2) + 2x - 6 - 2 {x}^(2) - 3x + 9$

$\qquad \sf  \dashrightarrow \: {x}^(2) - 2 {x}^(2) + 2x - 3x - 6 + 9$

$\qquad \sf  \dashrightarrow \: - {x}^(2) - x + 3$

For, (h - g)(2.1), put x = 2.1

$\qquad \sf  \dashrightarrow \: - {(2.1)}^(2) - (2.1) + 3$

$\qquad \sf  \dashrightarrow \: - 4.41 - 2.1 + 3$

$\qquad \sf  \dashrightarrow \: - 6.51 + 3$

$\qquad \sf  \dashrightarrow \: - 3.51$

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