Answer:
x = 9, y = 13 , z = - 19
Explanation:
3y + 4z = - 37 → (1)
2x + 4y - 3z = 127 → (2)
4y = 52 → (3)
divide both sides by 4 in (3)
y = 13
substitute y = 13 into (2) and solve for z
3(13) + 4z = - 37
39 + 4z = - 37 ( subtract 39 from both sides )
4z = - - 76 ( divide both sides by 4 )
z = - 19
substitute y = 13 and z = - 19 into (2) and solve for x
2x + 4(13) - 3(- 19) = 127
2x + 52 + 57 = 127
2x + 109 = 127 ( subtract 109 from both sides )
2x = 18 ( divide both sides by 2 )
x = 9
solution is x = 9, y = 13 , z = - 19