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Polynomial Question
Find the roots if one of the roots is the product of the other two

Polynomial Question Find the roots if one of the roots is the product of the other-example-1
User Susan
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1 Answer

4 votes

Explanation:

x³ - x² - 24x - 36

factors of -36 are 1, 2, 3, 4, 6, 9, 12, 18, 36 and negative equivalents.

1 - 1 - 24 - 36 != 0

8 - 4 - 48 - 36 != 0

27 - 9 - 72 - 36 != 0

64 - 16 - 96 - 36 != 0

216 - 36 - 144 - 36 = 0

So one factor is 6

x = 6

(x - 6) = 0

x²(x - 6) = x³ - 6x²

5x(x - 6) = 5x² - 30x

6(x - 6) = 6x - 36

x³ - 6x² + 5x² - 30x + 6x - 36

(x - 6)(x² + 5x + 6)

(x - 6)(x² + 3x + 2x + 6)

(x - 6)(x(x + 3) + 2(x + 3))

(x - 6)(x + 3)(x + 2)

x - 6 = 0

x = 6

x + 3 = 0

x = -3

x + 2 = 0

x = -2

x = -2, -3, 6.

One is the product of the other 2 as -2 x -3 = 6.

Graphic proof is shown above or below in the image

Polynomial Question Find the roots if one of the roots is the product of the other-example-1
User Elim
by
7.2k points