The value of x in Fe(NH₂)₂(SO4)₂ xH₂O can be found by determining the amount in mol of sulfate in the compound. A 0.982 g sample was dissolved in water and excess BaCl₂(aq) was added. The precipitate of BaSO, was separated and dried and found to weigh 1.17 g.
a) Calculate the amount, in mol, of BaSO4 in the 1.17 g of precipitate.
b) Calculate the amount, in mol, of sulfate in the 0.982 g sample of Fe(NH₂)₂(SO4)₂ XH₂O.
c) Calculate the amount, in mol, of iron in the 0.982 g sample of Fe (NH₂)₂(SO4)2 xH₂O.
d) Determine the mass, in g, of the following present in the 0.982 g sample of Fe(NH₂)₂(SO₂)₂ xXH₂O:
(i) iron (ii) ammonium (iii) sulfate.
e) Use your answer from part (d) to determine the amount in mol of water present in the 0.982 g sample of Fe(NH₂)₂(SO4)₂ xH₂O.