Question

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Answer 1

Answer: $3 / hot dog

Explanation:

Given information:

1 hot dog + 1 pretzel = $5

2 hot dogs + 3 pretzels = $12

Set variables:

Let x be the price per hot dog

Let y be the price per pretzel

Set system of equations:

x + y = 5

2x + 3y = 12

Multiply the first equation by 3:

3x + 3y = 15

2x + 3y = 12

Subtract the second equation from the first equation (Elimination):

(3x + 3y) - (2x + 3y) = 15 - 12

3x + 3y - 2x - 3y = 3

(3y - 3y) + 3x - 2x = 3

0 + x = 3

`\boxed{x=3}`

Hope this helps!! :)

Please let me know if you have any questions

Answer 2

pretzel: 2

hotdog: 3

Explanation:

Let h be the hotdog price and p the pretzel price.

We know that:

h + p = 5

and

2h + 3p = 12

We can solve this system of equations:

h = 5-p

2(5-p) + 3p = 12

So the second eq. becomes:

10 - 2p + 3p = 12

10 + p = 12

p = 2

Sub in the first:

h = 5 - p = 5-2 = 3

So p = 2, h = 3