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What are the solutions of the system of equations y = –(x + 2)2 + 1 and y = 2x + 5?

A (–4, –3) and (–2, 1)
B (–4, –3) and (2, 1)
C (–4, 5) and (2, 1)
D (–4, 5) and (–2, 1)

User Fabrice
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1 Answer

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A - plug in and solve

y = -(x+2)^2+1
-3 = -(-4+2)^2+1
-3 = -(-2)^2+1
-3 = -4 +1
-3 = -3

y = -(x+2)^2+1
1 = -(-2+2)^2+1
1 = 0^2+1
1 = 1

y = 2x+5
-3 = 2(-4)+5
-3 = -8+5
-3=-3

y = 2x+5
1 = 2(-2) + 5
1 = -4+5
1=1
User Babken
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