Question

Find the equation of the line passing through the points (3,7) and (-2,5)

Answer 1

The equation of the line passing through the points (3,7) and (-2,5) is y=⅖x+29/5

Explanation:

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`first \: find \: the \: slope \: m \\ m = ((Y₂-Y₁))/((X₂-X₁)) ..substitute \: vlues \\ m = ((5 - 7))/(( - 2 - 3)) = ( - 2)/( - 5) = (2)/(5) \\ y = mx + b \: to \: find \: equation \: of \: aline \\ between \: two \: poins and \: use \: \\ one \: of \: the \: two \: points \: lets \: take( - 2.5) \\ y = mx + b \\ 5 = ( - 2)/(5) ( - 2) + b \\ 5 = ( - 4)/(5) + b \\ 5 + { - 4}^(5) = b \\ (25 + 4)/(5) = b \\ b = (29)/(5) \\ finally \: equation \: of \: the \: line \: will \: be \\ y = (2)/(5) x + (29)/(5)`