Question

In order to dilute 40.0 mL of 0.600 M HCl to 0.200 M, the volume of water that would need to be added would be 200 mL. 80.0 mL. O 160 mL. 120 mL. 100 mL.​

Answer 1

80 ml

Step-by-step explanation:

Moles to start = .04 L * .6 M/L = .024 moles

this is how much must be in the final dilution

.2 moles / liter * x liter = .024 moles

x = .024 / .2 = .12 liter final volume

start with . 040 then add .080 to get .12 liter

.080 liter = 80 ml