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A sample of a gas (15.0 mol) at 2.0 atm is expanded at constant temperature from 5 L to 19.5 L. calculate the final pressure.​

1 Answer

6 votes

Answer:

.512 ATM

Step-by-step explanation:

P1V1 = P2V2

2 * 5 = P2 * 19.5

P2 = .512 ATM

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