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Let Xi = (i =1,2,3) be independently and normally distributed random variable with mean of 4 as variance i. state the distribution of the following random variable

i) V = X1+X2+X3

User Holmes IV
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1 Answer

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The sum of normally distributed random variables is also a normally distributed random variable.

Given
n random variables with
X_i\sim\mathrm{Normal}(\mu_i,\sigma_i^2), their sum is


\displaystyle\sum_(i=1)^n X_i \sim \mathrm{Normal}\left(\sum_(i=1)^n \mu_i, \sum_(i=1)^n \sigma_i^2\right)

i.e. normally distributed with mean and variance equal to the sums of the means and variances of the
X_i.

In this case, each of
X_1,X_2,X_3 are normally distributed with
\mu=4 and
\sigma^2 = ... I'm not sure what you meant for the variance, so I'll keep it symbolic. Then


V = X_1+X_2+X_3 \sim \mathrm{Normal}(12, 3\sigma^2)

User Vitalizzare
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