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What is the expected value when rolling a fair 12-sided die?

A. 7.5
B. 5.35
OC.7
D. 6.5

User Zzzeek
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D become more of the day to day
User Stefan Ollinger
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Answer:

What is the expected value when rolling a fair 12-sided die?

132=6.5

Recall the definition of the expected value:

E[X]=∑ni=1xp(x)

Here, we have 12 possible values the die can take on, and the probability of each one is the same: 1/12. So we can just pull the term p(x), the probability of each outcome, out of the summation:

E[X]=112∑12i=1x

A useful trick here is that the sum of the numbers 1..N=N(N+1)2. So:

E[X]=11212(13)2

E[X]=12(13)12(2)

E[X]=132

Explanation:

hope it helps you :)

User Daniel Cumings
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