Question

(Refer to the attached image)​

Answer 1

Formula given by

`\boxed{\sf Distance=√((x_2-x_1)^2+(y_2-y_1)^2)}`

`\\ \tt{:}\longrightarrow D=√((-4-4)^2+(3+3)^2)`

`\\ \tt{:}\longrightarrow D=√(8^2+6^2)`

`\\ \tt{:}\longrightarrow D=√(10^2)`

`\\ \tt{:}\longrightarrow D=10units`

Option D

Answer 2

D. 10

Explanation:

To find the distance between two points, use the distance formula:

Distance between two points

`d=√((x_2-x_1)^2+(y_2-y_1)^2)`

`\textsf{where }(x_1,y_1) \textsf{ and }(x_2,y_2)\:\textsf{are the two points}`

Define the two points:

`\textsf{Let }(x_1,y_1)=(4,-3)`

`\textsf{Let }(x_2,y_2)=(-4,3)`

Substitute the two defined points into the distance formula and solve for d:

`\implies d=√((-4-4)^2+(3-(-3))^2)`

`\implies d=√((-4-4)^2+(3+3)^2)`

`\implies d=√((-8)^2+6^2)`

`\implies d=√(64+36)`

`\implies d=√(100)`

`\implies d=√(10^2)`

`\implies d=10`

Therefore, the distance between the two given points is 10 units.