Question

If butane had a volume of 500 mL. at a pressure of 1.5 atm and a temperature of

20 °C, what would the new volume of the gas be at a temperature of 30 °C and a pressure
of 500 Torr

Answer 1

Question:

If butane had a volume of 500 ml. at a pressure of 1.5 atm and a temperature of 20 °C, what would the new volume of the gas be at a temperature of 30 °C and a pressure of 500 Torr?

Solution Given:

Let P be the pressure V be volume and and T be temperature.

Volume of Butane [
`V_1`] = 500 ml

Pressure of Butane [
`P_1`] = 1.5 atm

Temperature [
`T_1`] =20°C=20+273=293K

New Volume of Butane [
`V_2`] = ?

New Pressure of Butane [
`V_2`] =500 Torr=500*0.00131579=0.657895 atm

Note: 1 Torr= 0.00131579 atm

New Temperature of Butane [
`V_2`] =30°C=30+273=303K

Now

By using combined gas law equation:

`V_2=V_2*(P_1*T_2)/(P_2*T_1)`

`V_2=500*(1.5*303)/(0.657895*293)=1178.9 ml`

The new volume of Butane is 1178.9 ml