Question

Write a linear function that passes through the points (3, -7) and (0, 15)

Answer 1

The linear function for the given pts. will be

`y = ( - 22)/(3)x + 15`

Explanation:

Hello!

`first \: find \: the \: slope \: for \: the \: two \: pts. \\ m = (y2 - y1)/(x2 - x1) \\ m = ((15 - ( - 7)))/((0 - 3)) where \: y2 = 15 \\ y1 = - 7 \\ x2 = 0 \\ x1 = 3 \\ m = ( - 22)/(3) \\ thus \: y = mx + b \: \: solve \: for \: b \: using \: one \: of \: the \: two \: points \\ lets \: take \: the \: second \: point \\ y = mx + b \\ 15 = ( - 22)/(3) (0) + b \\ b = 15 \\ therefore \: substitute \: this \: value \: to \: get \: the \: \\ y = ( - 22)/(3) x + 15`