Answer:


Explanation:
To solve simultaneous equations, at least one of our variables must have the same coefficient. We can easily multiply the first equation by 4 to get 12y on both sides, so let's do that:

No let's subtract the second equation from the first equation to get the third equation:

Solve:

Now, we can substitute this value into one of the original equations - let's use the second one:

Solve:

