Question

Evaluate: sigma 32 and n=1 (2n+8)

Answer 1

Not sure but I think its 4n+90)

Explanation:

don't go with my answer to be safe

Answer 2

`\sum_(n=1)^(32) 2n+8 =1312`

Explanation:

I assume you are looking for
`\sum_(n=1)^(32) 2n+8 \\`:

`\sum_(n=1)^(32) 2n+8 \\`

`\sum_(n=1)^(32) 2n+\sum_(n=1)^(32) 8 \\`

`2\sum_(n=1)^(32) n+32(8)`

`2((32(32+1))/(2))+256`

`2(528)+256`

`1056+256`

`1312`