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If I have 4.5 liters of gas at a temperature of 33 0C and a pressure of 6.54 atm, what will be the pressure of the gas if I raise the temperature to 94 0C and decrease the volume to 2.3 liters?

User Kovogel
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2 Answers

3 votes

Answer:

15.35 atm

Step-by-step explanation:

Combined Gas Law


\sf (P_1V_1)/(T_1)=(P_2V_2)/(T_2)

Temperature must be in kelvins (K).

To convert Celsius to kelvins, add 273.15.

Volume can be in any unit.

Given values:

  • P₁ = 6.54 atm
  • V₁ = 4.5 L
  • T₁ = 33 °C = 33 + 273.15 = 306.15 K
  • P₂ =
  • V₂ = 2.3 L
  • T₂ = 94 °C = 94 + 273.15 = 367.15 K

Rearrange the equation to isolate P₂:


\sf \implies P_2=(P_1V_1T_2)/(V_2T_1)

Substitute the given values into the equation:


\sf \implies P_2=(6.54 \cdot 4.5 \cdot 367.15)/(2.3 \cdot 306.15)


\sf \implies P_2=15.34516967

Therefore, the pressure of the gas will be 15.35 atm (2 d.p.).

User Custodio
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8.6k points
0 votes

This is an exercise in the general or combined gas law.

To start solving this exercise, we must obtain the following data:

Data:

  • V₁ = 4.5 l
  • T₁ = 33 °C + 273 = 306 k
  • P₁ = 6.54 atm
  • T₂ = 94 °C + 273 = 367 k
  • V₂ = 2.3 l
  • P₂ = ¿?

We use the following formula:

  • P₁V₁T₂ = P₂V₂T₁ ⇒ General Formula

Where

  • P₁ = Initial pressure
  • V₁ = Initial volume
  • T₂ = Initial temperature
  • P₂ = Final pressure
  • V₂ = Final volume
  • T₁ = Initial temperature

We clear the general formula for the final pressure.


\large\displaystyle\text{$\begin{gathered}\sf P_(2)=(P_(1)V_(1)T_(2) )/(V_(2)T_(1)) \ \to \ Clear \ formula \end{gathered}$}

We solve by substituting our data in the formula:


\large\displaystyle\text{$\begin{gathered}\sf P_(2)=\frac{(6.54 \ atm)(4.5 \\ot{l})(367 \\ot{K}) }{(2.3 \\ot{l})(306 \\ot{k})} \end{gathered}$}


\large\displaystyle\text{$\begin{gathered}\sf P_(2)=(10800.81)/( 703.8 ) \ atm \end{gathered}$}


\boxed{\large\displaystyle\text{$\begin{gathered}\sf P_(2)=15.346 \ atm \end{gathered}$} }

If I raise the temperature to 94°C and decrease the volume to 2.3 liters, the pressure of the gas will be 15,346 atm.

User Frank Perez
by
8.2k points

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