Question

What volume of barium chloride, BaCl2 is needed to make a 2.5 M barium

chloride solution with 0.45 mol BaCl2?

Answer 1

0.18 L

Step-by-step explanation:

You can find the volume using the molarity ratio:

Molarity = moles / volume (L)

You can plug the given values into the equation and simplify to find the volume.

Molarity = moles / volume <----- Molarity ratio

2.5 M = 0.45 moles / volume <----- Insert values

(2.5 M) x volume = 0.45 moles <----- Multiply both sides by volume

volume = 0.18 L <----- Divide both sides by 2.5