Question

. What is the potential energy of a 0.40 kg ball at a height of 9.2 m?​

Answer 1

Step-by-step explanation:

gravitational potential energy = mgh (must be in S.I. unit)

m= 0.4 kg ; g= 10m/s (gravitational acceleration occurs); h=9.2 m

hence mgh=0.4×10×9.2= 36.8J

unit for energy is joules and since the variables are in S.I. unit, we can use Joules as the final unit for measurement

Answer 2

36.06 J if you define g = 9.8 m/s² or 36.8 J if you define g = 10 m/s²

Step-by-step explanation:

Potential Energy = Mass x Gravitational Acceleration x Height

It can be expressed as
`\displaystyle{PE = mgh}` where PE is potential energy, m is mass, g is gravitational acceleration and h is height.

In this case, we know mass is 0.40 kg and height of 9.2 m as well as gravitational acceleration is defined to be 9.8 m/s² (You can also define g = 10 m/s²)

Therefore, substitute given information in formula:

`\displaystyle{PE=0.40 \ * \ 9.8 \ * 9.2 }\\\\\displaystyle{PE=36.06 \ J}`

With g = 10 m/s², you'll get:

`\displaystyle{PE = 0.40 \ * 10 \ * 9.2}\\\\\displaystyle{PE = 36.8 \ J}`

Note that J is for joule unit.

Therefore, the answer is 36.06 J if you define g = 9.8 m/s² or 36.8 J if you define g = 10 m/s² - both work.