Question

a ball of mass 0.5 kg is released from rest at a height of 30 m. how fast is it going when it hits the ground? acceleration due to gravity is g = 9.8 m/s^2

Answer 1

24.25m/s

Step-by-step explanation:

m = 0.5kg

u ( initial velocity) = 0m/s

v ( final velocity) =?

a = 9.8m/s^2

d (displacement) = 30m

Since u don't have time, u only have the choice to use this formula

V^2 = u^2 + 2ad

V^2 = 0 + 2 x 9.8 x 30

V^2 = 588

V = 24.25 m/s