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1 vote
Find the zeros of the following
please solve step by step
1. x³+9x²+26x+24=0

User Lajosdeme
by
3.1k points

1 Answer

5 votes

Answer: -4, -3, -2

Explanation:

By inspection, we know
x=-2 is a root.

We can thus rewrite the equation as


(x+2)\left((x^3 + 9x^2 + 26x+24)/(x+2) \right)=0\\\\(x+2)(x^2 + 7x+12)=0\\\\(x+2)(x+3)(x+4)=0\\\\x=-4, -3, -2

User Quang Vinh
by
3.4k points