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A primary current of 6.0 A exists in an ideal iron-core transformer at a primary voltage of 100 volts. If the current in the secondary is 0.75 A, calculate the output voltage.

1 Answer

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Answer:

Step-by-step explanation:

Formula

Voltage_p * Current_p = Voltage_s * Current_s

Comment

What the formula means is the voltage multiplied by the current in the primary = voltage multiplied by the current in the secondary.

Givens

Vp =100 v

Ip = 6 amps

Vs = x

Is = 0.75 amps

Solution

100 * 6 = 0.75* x

600 = 0.75 x Divide both sides by 0.75

600/0,75 = 0.75x/0.75

800v = x

What you have here is a step up transformer. It has a relatively small voltage (100 volts ) on the primary which the transformer changes to 800 volts in the secondary.

Answer

800 volts.

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