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You need a 75 % alcohol solution. On hand, you have a 260 mL of a 30% alcohol mixture. You also have 95 % alcohol mixture . How much of the 95% mixture will you need to add to obtain the desired solution? You will need mL of the 95% solution

2 Answers

3 votes

Answer:

You will need 585 mL of the 95% solution.

Explanation:

You need a 75 % alcohol solution. On hand, you have a 260 mL of a 30% alcohol mixture-example-1
User Josh Handel
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30 \: percent \: alcohol \: in \: 260 \: ml \\ alcohol = 0.3 * 26 0= 78 \: ml


c( \gamma ) = (78 + </strong><strong>0</strong><strong>.</strong><strong>9</strong><strong>5</strong><strong>\gamma )/(260 + \gamma ) * 100


c( \gamma ) = 75


(78 + </strong><strong>0</strong><strong>.</strong><strong>9</strong><strong>5</strong><strong>\gamma )/(260 + \gamma ) = 0.75


78 + </strong><strong>0</strong><strong>.</strong><strong>9</strong><strong>5</strong><strong>\gamma = 0.75 \gamma + 195 \\ 0.2 \gamma = 117 \\ \gamma = </strong><strong>5</strong><strong>8</strong><strong>5</strong><strong>


we \: need \: </strong><strong>5</strong><strong>8</strong><strong>5</strong><strong> \: ml \: of \: </strong><strong>9</strong><strong>5</strong><strong>%</strong><strong> \: alcohol

User Olga
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