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F(x)=x^2-x-56=0 what are the zeros in the function?
please help!!!

1 Answer

5 votes

Answer:

-7, 8.

Explanation:

x^2 - x - 56 = 0

Let's see if we can factor this function:

We need 2 numbers whose product is -56 and whose sum is -1 ( which is the coefficient of x).

They are -8 and 7 , so the factors are:

(x - 8)(x + 7) = 0

x - 8 = 0 giving x = 8 and

x + 7 = 0 giving x = -7.

The zeros are -7, 8

User Romain Pellerin
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