Question

Someone help quickly pls :(

Assignment
Practice finding solutions to systems of equations using
substitution.
The value of x in this system of equations is 1.
3x + y = 9
y=-4x+10
1. Substitute the value of y in the first equation:
2. Combine like terms:
3. Apply the subtraction property of equality:
4. Apply the division property of equality:
What is the value of y?
y=
3x + (-4x+10) = 9
-x+10=9
-x=-1
x=1

Answer 1

y = 6

Explanation:

Answer 2

y = 6

Explanation:

Solving system of linear equation using substitution method:

3x + y = 9 ---------------(I)

y = -4x + 10 -----------------(II)

Substitute y = -4x + 10 in equation (I)

3x - 4x + 10 = 9

Combine like terms,

-x + 10 = 9

Subtract 10 from both sides. (subtraction property of equality)

-x = 9 - 10

-x = -1

Divide both sides by (-1). {Division property of equality}

`\sf (-x)/(-1)=(-1)/(-1)\\\\ \boxed{x = 1}`

Now, substitute x = 1 in equation (II) and find the value of y.

y = -4*1 + 10

= -4 + 10

`\sf \boxed{\bf y = 6}`