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Please help!

Sierra has a total of 61 dimes and quarters in her piggybank. She has 3 more quarters than dimes. The coins have a total value of $10.90. How many dimes and how many quarters does she have?

last one was unanswered lol

User Michael Pankov
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1 Answer

24 votes
24 votes

Answer:

First, denote the number of dimes as x, and the number of quarters as y.

Since the total number of coins equals 61, we can write the following equation: x + y = 61

Since the total value of the coins equals $10.90, and we know that a quarter is worth $0.25 and a dime is worth $0.10, the total value can be expressed as a function of the number of quarters and dimes: $0.10*x + $0.25*y = $10.90

Now, we have two equations and two variables, meaning we can solve the 2x2 system!

Rewrite the first equation in terms of x: x = 61 - y

Now substitute this expression into the second equation: $0.10*(61-y) + $0.25*y = $10.90

Solve for y: $.15*y = $4.80, y = 32

Substitute back into the first equation to get x: x = 29

She indeed has 3 more quarters than dimes since 32-29= 3, so we did it right (:

Explanation:

User Joey Clover
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