Question

The weight of football players is normally distributed with a mean of 180 pounds and a standard deviation of 20 pounds. what is the probability of a player weighing less than 215 pounds?

Answer 1

Given:

mu = 200 lb, the mean sigma = 25 the standard deviation

For the random variable x = 250 lb, the

z-score is z = (x - mu) / sigma = (250 - 200) / 25 = 2

From standard tables for the normal distribution, obtain

P(x < 250) = 0.977

Answer: 0.977