Question

Q2. A force of 1000N is experienced by a charge in a field of strength of 250NC. Find the value of the charge establishing the field.​

Answer 1

4 C

Step-by-step explanation:

The strength of an electric field can be defined as:
`E = (f)/(q)` where f=force and q=charge, and e=strength

Since we're given the strength and the force we can simply rearrange the equation so that we solve for Q:

Original Equation:

`E=(f)/(q)`

Multiply both sides by q

`E*q = f`

Divide both sides by E

`q=(f)/(e)`

So now plug the known values into the equation

`q=(1000 N)/(250 N/C)`

Simplify:

`q = 4 c`