x + 4y = 16 __(1)
3x + 5y = 27 __(2)
Multiply the 1st equation by 3
3x + 12y = 48 __(3)
Solving (2) and (3)
3x + 12y = 48
3x + 5y = 27
__________
(-) (-) (-)
7y = 21
So, y = 3
By, putting the value of y = 3 in equation 1
x + 4(3) = 16
x + 12 = 16
x = 16 - 12
x = 4
We got -
The value of x = 4 and y = 3
Hope it helps you any confusions you may ask!