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A bag contains 15 counters:7 red 4 blue and 4 green.a counter is taken out of the bag at random.what is the probability of choosing the following: a red or blue counter.



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|\Omega|=15\\|A|=7+4=11\\\\P(A)=(11)/(15)\approx73.3\%

User Brendan Hill
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Answer:

RED COUNTER: 7/15

BLUE COUNTER: 4/15

Hope it helps,

for further explanation do contact me

User Tyger Guzman
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