Question

7. Find the equation of the line passing through the
points P(-2,7) Q(2,-3)

Answer 1

Answer: y=
`-(5)/(2) x+2`

Explanation:

Use the equation of the line format: y = mx + b

`m=(y2-y1)/(x2-x1)`

`m=(-3-(7))/(2-(-2))`

`m=(-10)/(4)`

simplified

`m=(-5)/(2)`

in order to find B:

`y = -((5)/(2)) *(-2)+b`

Insert value of y:

`7 = (-(5)/(2) ) * (-2) +b`

Rewrite:

`-(5)/(2) * -2 - b=7`

Cancel the common factor of 2:

`-5 * -1 +b = 7`

Multiply -5 by -1:

`5 + b= 7`

Subtract 5 from both sides:

`b = 7-5\\b=2`

Now substitute values of m, and the final answer is:

`y = -(5)/(2)x + 2`