Part A

Part B

So, the x-intercepts are
and

Part C
As
,
because the leading coefficient is positive.
As
,
because the degree is even and the leading coefficient is positive.
Part D
Plot the x-intercepts on the graph, and then find the value of
at
(the midpoint of the two roots) to plot the vertex. Then, draw a curve through these three points that approaches infinity as
