Find the h.c.f of {x}^{3} + {y}^{3} \: and \: \: {x}^{2} - xy + {y}^{2}x 3 +y 3 andx 2 −xy+y 2

asked Jul 22, 2023 98.7k views

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Factorize the sum of cubes:

x^3 + y^3 = (x+y) (x^2 - xy + y^2)

so
x^2-xy+y^2 is a factor of
x^3+y^3 . Then the HCF is
$\boxed{x^2 - xy + y^2}$ .

Flight answered Jul 27, 2023

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